5
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Tutorials too long. Quick guide?

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2 Answers 2

5
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$x$

$x$

$$ x + y^{2k} $$

$$
x + y^{2k}
$$

Inline $x + y$ with text

Inline $x + y$ with text

$$ a \leq \frac{b}{c} $$

$$
a \leq \frac{b}{c}
$$

$$ y[n] = \sum_{k=0}^{m} b_k $$

$$
y[n] = \sum_{k=0}^{m} b_k 
$$

$$ \mathbf M = \begin{pmatrix} 1 & 2 & \pi \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{pmatrix} $$

$$
\mathbf M = 
\begin{pmatrix}
  1 & 2 & \pi \\
  4 & 5 & 6 \\
  7 & 8 & 9
\end{pmatrix}
$$

$$ \int_{-\infty}^{\infty} \hat\psi_{a,b}(\omega) d\omega, \omega \in \mathbb{R} $$

$$
\int_{-\infty}^{\infty} \hat\psi_{a,b}(\omega) d\omega, \omega \in \mathbb{R} 
$$

Greek Alphabet

Math symbols


$$ f(n) = \begin{cases} n/2, & \text{if $n$ is even} \\ \sqrt{3n+1}, & \text{if $n$ is odd} \end{cases} $$

$$
f(n) =
\begin{cases}
n/2, & \text{if $n$ is even} \\
\sqrt{3n+1}, & \text{if $n$ is odd}
\end{cases}
$$

\begin{align} 5 &= 0.5^{-1} + 3 \\ &= 2 + 3 \\ &= \boxed{5} \tag{1}\label{1} \\ \end{align}

\begin{align}
5 &= 0.5^{-1} + 3 \\
&= 2 + 3 \\
&= \boxed{5} \tag{1}\label{1} \\
\end{align}

And in $\eqref{1}$ we see that the result is five.

And in $\eqref{1}$ we see that the result is five.
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2
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Advanced

MathJax reference -- $$ omitted below

$$ \mathbf I = \begin{pmatrix} 1 & 0 & \cdots & 0\\ 0 & 1 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & \cdots & 1 \end{pmatrix} $$

\mathbf I = 
\begin{pmatrix}
  1      & 0      & \cdots & 0\\
  0      & 1      & \cdots & 0 \\
  \vdots & \vdots & \ddots & \vdots \\
  0      & 0      & \cdots & 1
\end{pmatrix}

$$ \cos(\omega_0 t) \Leftrightarrow \pi \delta(|w| - \omega_0) $$

\cos(\omega_0 t) \Leftrightarrow \pi \delta(|w| - \omega_0)
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  • $\begingroup$ Feel free to add stuff here, I rather keep the main answer simple $\endgroup$ Sep 5, 2021 at 9:53

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